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3x^2-3333x+7=0
a = 3; b = -3333; c = +7;
Δ = b2-4ac
Δ = -33332-4·3·7
Δ = 11108805
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3333)-\sqrt{11108805}}{2*3}=\frac{3333-\sqrt{11108805}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3333)+\sqrt{11108805}}{2*3}=\frac{3333+\sqrt{11108805}}{6} $
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